Ph of oh- 1x10-8
WebThe [H +] of a solution is 8.34 x 10 -5 mole/liter. The pH of this solution lies between: ? 2 and 3. ? 4 and 5. ? 5 and 6. WebMay 16, 2024 · From pH = 8.60, we can find [H +] and hence [OH - ]. [H +] = 1x10 -8.60 = 2.51x10 -9 M [OH -] = 1x10 -14 /2.51x10 -9 = 3.98x10 -6 M (This can also be found from pOH: pOH = 14-pH = 14-8.60 = 5.4 and OH = 10 -5.4 = 3.98x10 -6 M) Kb = (3.98x10 -6 ) (3.98x10 -6 )/0.016 - 3.98x10 -6 and assuming 3.98x10-6 is small relative to 0.016, ignore it...
Ph of oh- 1x10-8
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WebVerificar: Ca>100Ka y [H3O+]<0,05∗Ca 𝟏𝒙𝟏𝟎−𝟒 > 𝟒𝒙𝟏𝟎−𝟖 𝒚 𝟐𝒙𝟏𝟎−𝟕 < 𝟓𝒙𝟏𝟎−𝟔 Verificar: 𝑶𝑯− < 𝟎, 𝟎𝟓 [𝑯𝟑 𝑶+ ] 𝟓𝒙𝟏𝟎−𝟖 < 𝟏𝒙𝟏𝟎−𝟖 No cumple Ejemplo 2: Calcule la [H3O+] y el pH en una solución 10-4 M HCN. WebJun 2, 2024 · Calculate the PH of 1 x 10 -8 M solution of HCl. equilibrium class-11 1 Answer 0 votes answered Jun 2, 2024 by faiz (316k points) selected Jun 2, 2024 by Golu Best …
WebJul 6, 2024 · pH = 14 - pOH and pOH = -log [OH-] = -log 4.5x10 -2 = 1.3. pH = 14 - 1.3 = 12.7. Or you could use [H 3 O + ] [OH-] = 1x10 -14 and solve for [H 3 O +] [H 3 O +] = 1x10 -14 … WebIf pH= 5.82 and pOH=14-pH pOH=14-5.82=8.18 [OH-]=10-p OH so [OH-]=10-8.18 [OH-]= 6.6x10-9 M. Example D. If [OH-]= 8.1x10-4 M and pOH =-log [OH-] pOH =-log 8.1x10-4 M …
WebMar 1, 2024 · There are a few different formulas you can use to calculate pOH, the hydroxide ion concentration, or the pH (if you know pOH): pOH = -log 10 [OH -] [OH -] = 10 -pOH pOH + pH = 14 for any aqueous solution … WebMathematically PH of OH- ion is 8, it looks correct value. But at very low concentrations, while calculating we must consider the concentration of OH- ions produced by water …
WebK w is an ionic product of water and its value is 1x10-14 at 25°C. [H +] [OH-] = 1x10-14 Pure water dissociate completely and has equal concentration. Thus [H +] = [OH-] [H +] [H +] = …
WebJun 10, 2024 · Divide both side by 1x10^-8 [H+] = 1x10^-14 / 1x10^-8 [H+] = 1x10^-6M. 4. Data obtained from the question include: pOH = 9. Hydrogen ion concentration, [H+] =..? … ihow can i enhace stars in photoshopWebAt 25ºC, Kw = [OH-] [H+] = 1x10-14 [OH-] = 1x10-14/ .2 = 5x10-14 b. 5 x 10-10 M [OH-] = 1x10-14/ 5 x 10-10 = 2 x 10-5 c. 100 M [OH-] = 1x10-14/ 100 = 1x10-16 3. For each of these strong acid/base solutions, calculate the molarity of OH-, H+, pH and pOH a. 0.01M NaOH [OH-] = 0.01 pOH = 2 [H+] = 1x10-14/.01 = 1x10-12 pH = 12 b. 5M HNO3 [H+] = 5 ... is there a flawless pool this weekendWebGUIA DE QUIMICA 11. Calcule la H+ Y LA OH- de las siguientes disoluciones Disolución de pH 6,2 [H+]= antilog-6,2 = 6,3x10-7 [OH-]= 1x10-14 / 6,3x10-7 = 1,5x10-8 [H+ ... i. how can we classify nonlinear dataWebMar 16, 2024 · The pH scale (pH) is a numeric scale used to define how acidic or basic an aqueous solution is. It commonly ranges between 0 and 14 but can go beyond these values if sufficiently acidic/basic. The pH value is logarithmically and is inversely related to the … ihow caravanWebPerform some calculations to complete the following table: [OH+] [H3O+] pH [H3O+]= 1X10^-5, find [OH+} and pH [OH-]= 1X10^-3, find [H3O+] and pH [H3O+]=1X10^-8, find [OH-], pH … is there a flatten function in excelWebLista de exercícios. 2) Encontre as concentrações ini ciais dos ácidos ou bases fracos em cada uma das. 3) Calcule K a e pK a ou K b e pK b para as seguintes soluções em água: a) 0,010 mol L -1 de ácido mandélico (anti-séptico) com pH = 2,95. 4) A porcentagem de ionização do ác ido benzóico em uma solução 0,110 mol L -1 é 2,4%. i. how do covalent compounds normally existWebNov 19, 2024 · Finding the pH: pH = -log [H⁺] pH = -log (10⁻¹⁰) pH = 10 Advertisement Brainly User Answer: given: abcissa (x-coordinate) of given point: -6 let's say the ordinate (y-coordinate) of the given point is y distance of the given point from (1,3) = √74 we can rewrite the given information as: the distance between the points (-6,y) and (1,3) is √74 is there a flash video game